# Welcome to the LEAP Q&A Forum

## GMAT - Problem Solving

Shah Tanjil 8 months ago

### Score 650?? (more)

I want to get 650 in GMAT exam. I am not a brilliant student. Is it possible for me get the desired mark? How can I start my preparation?

Hi Tanjil,

Through sustained efforts and regular practice, you will surely achieve your goal of a 650 GMAT score. Here is how you can use the QS- LEAP platform to start your prep:

• Start with going through the resources section which provides you with information on the syllabus of the test, concept notes to understand the nitty gritty of the topics under each section, myriad of videos that talk about strategies, the different question types etc.
•  On your QS- LEAP dashboard you can access practice tests that are divided into sections. Each test gives you an analysis on completion. This helps you to understand your strengths and areas of improvement. You will have a customized schedule based on the information you fill during registration. Your dashboard presents to you your daily goals in terms of the number of questions you need to solve.
• There is a forum called QNA wherein you can ask questions and clarify any doubt you have with regards to preparation or application.
• QS- LEAP even conducts Live Classes which you can attend for free. These classes provide you very good conceptual knowledge on different quant and verbal topics. These classes are conducted by experienced tutors from around the globe.

### A fruit-salad mixture consists of apples, peaches, and grapes in the ratio 6:5:2, respectively, by weight (more)

A fruit-salad mixture consists of apples, peaches, and grapes in the ratio 6:5:2, respectively, by weight. If 39 pounds of the mixture is prepared, the mixture includes how many more pounds of apples than grapes?

(A) 15
(B) 12
(C) 9
(D) 6
(E) 4

Assume the weight of apples be 6x

therefore wieght of peaches = 5x

weight of grapes = 2x

total weight = 6x + 5x + 2x = 13 x

39 = 13x

x = 3

weight of apples = 6x = 18

weight of grapes = 2x = 6

difference in weight = 18 - 6 = 12 pounds

B is correct

### The circle with center C shown above is tangent to both axes. If the distance from O to C is equal to k, what is the radius of the circle, in terms of k ? (more)

The circle with center C shown above is tangent to both axes. If the distance from O to C is equal to k, what is the radius of the circle, in terms of k ?

(A) k
(B) k/√2
(C) k/√3
(D) k/2
(E) k/3

Length from the origin to the point at which x axis touches the circle = radius of the circle = r (assume)

Length from the origin to the point at which y axis touches the circle = radius of the circle = r

Using pythagorus theorem

r2 + r2 = OC2 = k2

r = k/√2

B is correct

### An arithmetic sequence is a sequence in which each term after the first term is equal to the sum of the preceding term and a constant. If the list of numbers shown above i (more)

p, r, s, t, u

An arithmetic sequence is a sequence in which each term after the first term is equal to the sum of the preceding term and a constant. If the list of numbers shown above is an arithmetic sequence, which of the following must also be an arithmetic sequence?

I. 2p, 2r, 2s, 2t, 2u
II. p-3, r-3, s-3, t-3, u-3
III. p^2, r^2, s^2, t^2, u^2

(A) I only
(B) II only
(C) III only
(D) I and II
(E) II and III

given p, r, s, t u

are in AP

assume common difference be d

i.e.

r = p + d, s = p + 2d, t = p + 3d , u = p + 4d

I. 2p, 2r, 2s, 2t, 2u

2r = 2(p + d) = 2p + 2d

2s = 2(p + 2d) = 2p + 4d

2t = 2(p + 3d) = 2p + 6d

2u = 2(p + 4d) = 2p + 8d

they are in AP, with first term 2p and common difference 2d

II. p-3, r-3, s-3, t-3, u-3

r - 3 = p + d -3

s - 3 = p + 2d - 3

t - 3 = p + 3d - 3

u - 3 = p + 4d - 3

The sequence is in AP with first term p-3 and common diffrence d

We don't need to check third option as only Option D contains both I and II

### If Q is an odd number and the median of Q consecutive integers is 120, what is the largest of these integers? (more)

If Q is an odd number and the median of Q consecutive integers is 120, what is the largest of these integers?

(A) (Q - 1)/2 120
(B) Q/2 119
(C) Q/2 120
(D) (Q 119)/2
(E) (Q 120)/2

Let the first term be x

The largest term will be x + Q - 1

Median = (Q+1)/2 th term

Since the numbers are consecutive Median = x - 1 + (Q + 1)/2

120 = x - 1 + (Q+1)/2

x = 121 - (Q+1)/2

Largest term = x + Q - 1 = 121 - (Q+1)/2 - 1 = 120 + Q - Q/2 - 1/2 = 120 + (Q-1)/2

A is correct