Average Speed = (Total distance traveled) / (Total time taken)

Let’s say a person travels different distances d1 with speed s1 in Time t1, d2 with speed s2 in time t2, d3 with speed s3 in time t3 … and dn with speed sn in time tn.

So, the average speed, using the above formula is:

(d1+d2+d3+d4+…+dn)/(t1+t2+t3+t4+…+tn) = (s1*t1+s2*t2+s3*t3+…+sn*tn)/(t1+t2+t3+t4+…+tn) = (d1+d2+d3+d4+…+dn)/(d1/s1 + d2/s2 + d3 /s3 + d4/s4 +…+ dn/sn)

## What else you can do inside qs leap ?

Use any of the above 3 versions of the formula depending on the requirement.

Solve the following Data Sufficiency question-

**How much time did it take a certain car to travel 400 kilometers?**

**(1) The car traveled the first 200 kilometers in 2.5 hours**

**(2) If the car’s average speed had been 20 kilometers per hour greater than it was, it would have traveled the 400 kilometers in 1 hours less time than it did**