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GRE - Quantitative Reasoning - Factors & multiples

If xaybzc equals the product of 154 and 56, z > y > x, and a > b > c, and a, b, c, x, y, z are all positive integers, then what is the value of axbycz? (more)

If xaybzc equals the product of 154 and 56, z > y > x, and a > b > c, and a, b, c, x, y, z are all positive integers, then what is the value of axbycz?

A. 1,024
B. 2,048
C. 8,624
D. 22,528
It cannot be determined from the information given.

given:

xaybzc = 154*56 = 2*7*11*2*2*2*7 = 24*72*111 (We have way of writing this 42*72*111, both will give the same result)

x = 2, y = 7, z = 11, a = 4, b = 2, c = 1

thus,

axbycz = 42*27*111 = 16*128 = 2048

Option B is correct

How many positive integers less than 20 are factors of 96? (more)

How many positive integers less than 20 are factors of 96?

A. 5
B. 6
C. 7
D. 8
E. 9

Factors of 96 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48 and 96

Factors of 96 less than 20 - 1, 2, 3, 4, 6, 8, 12, 16

total number = 8

Which of the following is a factor of 18!+1? (more)

Which of the following is a factor of 18! 1?
A. 15 
B. 17 
C. 19 
D. 33 
E. 39

Two consecutive numbers never share a factor

factors of 18! include, 15, 17, 33 (11*3), 39 (13*3)

So the only correct option is 19